25m^2+5m-6=0

Solution for 25m^2+5m-6=0 equation:

25m^2+5m-6=0

a = 25; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·25·(-6)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-25}{2*25}=\frac{-30}{50}
=-3/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+25}{2*25}=\frac{20}{50}
=2/5
$